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Japan thoughts! — 3 Comments

  1. A.free energy = ?Gentropy chngae = ?Sb0?Sb0 = ?S products ?S reactants?Sb0 = 24.9?Gb0 = ?Hb0 T?Sb0?Gb0 = (90.25 1000) (25+273.15)x24.9?Gb0 = 82.83 KJ/molno this reaction will not work at 25 celciusB.A reaction becomes therodynamically favourable when ?G ? 0?Gb0 = ?Hb0 T?Sb00 = (90.25 1000) T x 24.9T= 3624.5Konly at very high tempratures does the reaction proceed.

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